Join 60,000+ competitive exam aspirants
If the radius of a sphere is increased by 20%, what is the percentage increase in its surface area?
40%
44%
48%
20%
44%
Use the formula 2x+100x2тАЛ for area percentage increase, where x is the percentage change in radius: 2(20)+100202тАЛ=40+4=44.
The radius of the sphere is increased by 20%.
Percentage┬аChange=x+y+100xyтАЛ
Use the formula 2x+100x2тАЛ for area percentage increase, where x is the percentage change in radius: 2(20)+100202тАЛ=40+4=44.
Many students wrongly assume the surface area increase is equal to the radius increase (20%), ignoring the quadratic relationship A=4╧Аr2.
Define the relationship
The surface area of a sphere is given by S=4╧Аr2. Since 4╧А is a constant, the area is directly proportional to the square of the radius, SтИЭr2.
S=4╧Аr2
Apply successive percentage formula
When a quantity changes by x% twice (due to the square), the total percentage change is given by the formula x+x+100x2тАЛ.
20+20+10020├Ч20тАЛ
Calculate the result
Substituting x=20 into the formula, we get 40+100400тАЛ=40+4=44%.
44%
B is correct because the successive increase of 20% on the radius leads to a total surface area increase of 44%.
This logic applies to any 2D area (like circles or squares); for 3D volume changes involving radius, use the factor (1+100rтАЛ)3тИТ1.