Join 60,000+ competitive exam aspirants
In тЦ│ABC, DEтИеAC, where D and E are the points on sides AB and BC, respectively. If BD=8┬аcm and AD=7┬аcm, then what is the ratio of the area of тЦ│BDE to the trapezium ADEC?
64 : 161
64 : 225
8 : 15
64 : 81
8 : 15
Since DE || AC, тЦ│BDEтИ╝тЦ│BAC. Area ratio is the square of side ratio (BD/BA)2=(8/15)2=64/225. Then, Area(Trapezium) = Area(Total) - Area(Small) = 225тИТ64=161. Ratio is 64:161.
Triangle ABC with DE || AC, BD = 8 cm, and AD = 7 cm.
Area(тЦ│ABC)Area(тЦ│BDE)тАЛ=(BABDтАЛ)2
Since DE || AC, тЦ│BDEтИ╝тЦ│BAC. Area ratio is the square of side ratio (BD/BA)2=(8/15)2=64/225. Then, Area(Trapezium) = Area(Total) - Area(Small) = 225тИТ64=161. Ratio is 64:161.
Students often take the ratio of sides directly as the ratio of areas (8/7) or forget that AB=BD+AD=8+7=15 cm.
Calculate AB
Since D lies on AB, the total length of segment AB is the sum of BD and AD.
AB=BD+AD=8+7=15┬аcm
Establish Similarity
Because DEтИеAC, тЦ│BDE is similar to тЦ│BAC by the AA criterion.
тЦ│BDEтИ╝\triangle BAC
Apply Area Ratio Theorem
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
\frac{\text{Area}(\triangle BDE)}{\text{Area}(\triangle BAC)} = \left(\frac{BD}{BA}\right)^2 = \left(\frac{8}{15}\right)^2 = \frac{64}{225}
Find Trapezium Area
The area of the trapezium ADEC is the difference between the total area of тЦ│BAC and the area of тЦ│BDE.
Area(ADEC)=Area(\triangle BAC)тИТArea(\triangle BDE)=225тИТ64=161
Calculate Final Ratio
The ratio of Area(тЦ│BDE) to Area(Trapezium ADEC) is 64:161.
Ratio=16164тАЛ
C is correct because using the properties of similar triangles, the ratio of areas is 64:161.
This concept is frequently used in Coordinate Geometry and Mensuration problems involving parallel lines cutting through triangles.