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ElectricalPower System
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In a power system, the 3-phase fault MVA is always higher than L-G fault MAV at bus

A

True

B

False

C

Insufficient data

Correct Answer

Concept & PrincipleElectricalPower System
Option A

True

Quick Summary: In a power system, the 3-phase fault MVA is generally the highest because it involves all three phases resulting in the minimum positive sequence impedance. Conversely, an L-G (Line-to-Ground) fault involves zero, positive, and negative sequence impedances, often leading to a lower fault current unless the zero-sequence impedance is significantly low.

💡 Explanation

In a power system, the 3-phase fault MVA is generally the highest because it involves all three phases resulting in the minimum positive sequence impedance. Conversely, an L-G (Line-to-Ground) fault involves zero, positive, and negative sequence impedances, often leading to a lower fault current unless the zero-sequence impedance is significantly low.

🔢 Key Formulas

MVA3ϕ=MVAbaseZ1(pu)MVA_{3\phi} = \frac{MVA_{base}}{Z_{1(pu)}}MVA3ϕ​=Z1(pu)​MVAbase​​ — 3-Phase fault MVA formula

MVALG=3×MVAbaseZ1(pu)+Z2(pu)+Z0(pu)MVA_{LG} = \frac{3 \times MVA_{base}}{Z_{1(pu)} + Z_{2(pu)} + Z_{0(pu)}}MVALG​=Z1(pu)​+Z2(pu)​+Z0(pu)​3×MVAbase​​ — L-G fault MVA formula

⚙️ Working Principle

The magnitude of fault current depends on the Thevenin equivalent impedance at the fault bus. For a 3-phase fault, If=VphZ1I_{f} = \frac{V_{ph}}{Z_{1}}If​=Z1​Vph​​, where Z1Z_{1}Z1​ is the positive sequence impedance. For an L-G fault, If=3VphZ1+Z2+Z0I_{f} = \frac{3V_{ph}}{Z_{1} + Z_{2} + Z_{0}}If​=Z1​+Z2​+Z0​3Vph​​. In most power systems (especially where grounding is high-impedance or the system is solidly grounded but with substantial Z0Z_{0}Z0​), the sum of sequence impedances results in a lower fault current than the direct 3-phase short-circuit case.

📌 Key Points
  • ▸

    3-phase faults are symmetric and utilize only positive sequence impedance.

  • ▸

    L-G faults utilize all three sequence networks (Positive, Negative, Zero).

  • ▸

    In systems where Z0Z_{0}Z0​ is high (e.g., resonant grounded systems), L-G fault current is significantly lower than 3-phase fault current.

  • ▸

    The statement is generally considered True for typical transmission network configurations.

🔄 Comparison Table
Feature3-Phase FaultL-G Fault

Sequence Networks Involved

Positive only (Z1Z_{1}Z1​)

Positive, Negative, Zero (Z1,Z2,Z0Z_{1}, Z_{2}, Z_{0}Z1​,Z2​,Z0​)

📄 Additional Information
  • ▸

    In cases where Z0Z_{0}Z0​ is very low, it is theoretically possible for L-G fault currents to exceed 3-phase currents, but standard power system practice assumes the 3-phase fault represents the maximum duty for circuit breakers.

  • ▸

    Option B is false because L-G faults are typically less severe in terms of current magnitude compared to symmetrical 3-phase faults in standard utility grids.

📊 Diagram / Illustration
Fault MVA Comparison
3-Phase Fault Current I3ϕ=VZ1I_{3\phi} = \frac{V}{Z_{1}}I3ϕ​=Z1​V​
L-G Fault Current ILG=3VZ1+Z2+Z0I_{LG} = \frac{3V}{Z_{1} + Z_{2} + Z_{0}}ILG​=Z1​+Z2​+Z0​3V​
Generally, I3ϕ>ILGI_{3\phi} > I_{LG}I3ϕ​>ILG​ due to sequence network sum
✅

A is correct — The 3-phase fault MVA is typically the maximum fault level in a power system because it involves only the lowest sequence impedance path (Z1Z_1Z1​).

Core Concepts Used
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Symmetrical Faults Unsymmetrical Faults Sequence Impedances
💡 EXAM TIP

Always remember that 3-phase faults provide the 'worst-case' scenario for circuit breaker sizing in most utility design standards.

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