Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
ಕೆಳಗಿನ ಸಮೀಕರಣದಲ್ಲಿ ‘+’ ಮತ್ತು ‘-‘ ವಿನಿಮಯಗೊಂಡರೆ ಮತ್ತು ‘x’ ಮತ್ತು ‘÷’ ವಿನಿಮಯಗೊಂಡರೆ ‘?’ ನ ಸ್ಥಾನದಲ್ಲಿ ಏನು ಬರುತ್ತದೆ?
22 ÷ 11 x 11 + 50 - 32 =?
4
6
5
2
4
Apply BODMAS after swapping operators: Replace ÷ with ×, × with ÷, + with -, and - with +.
Apply BODMAS after swapping operators: Replace ÷ with ×, × with ÷, + with -, and - with +.
Interchange Operators
Replace the signs according to the instruction: '÷' becomes '×', '×' becomes '÷', '+' becomes '-', and '-' becomes '+'. The equation becomes: 22 × 11 ÷ 11 - 50 + 32.
Apply BODMAS
Follow BODMAS (Bracket, Of, Division, Multiplication, Addition, Subtraction). First, divide: 11 ÷ 11 = 1. Equation becomes: 22 × 1 - 50 + 32.
Solve Remaining Operations
Next, multiply: 22 × 1 = 22. Now add positive numbers: 22 + 32 = 54. Finally, subtract: 54 - 50 = 4.
B: 6 is incorrect as the arithmetic result is 4. C: 5 is incorrect based on the standard BODMAS evaluation. D: 2 is incorrect as it fails to account for the correct order of operations after replacement.
A is correct because applying the interchanged operators 22 * 11 / 11 - 50 + 32 and solving via BODMAS yields 22 - 50 + 32 = 4.
In symbol interchange problems, always write the new equation clearly before calculating to avoid missing a sign change.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants