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P and Q can complete a task in 10 days and 15 days respectively. They work together for 3 days and then Q leaves. How many more days will P take to finish the remaining work?
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Assume total work as the LCM of individual days (30 units), find daily rates, subtract work done in 3 days, and divide remaining work by P's rate.
P's time = 10 days, Q's time = 15 days, Time worked together = 3 days
T=rPтАЛWтИТ(rPтАЛ+rQтАЛ)├ЧtтАЛ
Assume total work as the LCM of individual days (30 units), find daily rates, subtract work done in 3 days, and divide remaining work by P's rate.
Students often calculate the total time from the start instead of specifically finding 'how many more days' P takes for the remaining work.
Find Total Work and Daily Rates
Assume total work is the LCM of 10 and 15, which is 30 units. P's 1-day work is 1030тАЛ=3 units/day and Q's 1-day work is 1530тАЛ=2 units/day.
LCM(10,15)=30
Calculate Work Done Together
Combined 1-day work of P and Q is 3+2=5 units/day. In 3 days, they complete 5├Ч3=15 units of work.
WdoneтАЛ=(3+2)├Ч3=15
Determine Remaining Work
Subtract the work done from the total work to find the remaining work: 30тИТ15=15 units.
WremтАЛ=30тИТ15=15
Calculate Days Needed by P
Since Q leaves, P completes the remaining 15 units alone at a rate of 3 units/day, taking 315тАЛ=5 days.
T=315тАЛ=5
B is correct because P takes 5 more days to complete the remaining 15 units of work alone.
This LCM-based unit approach can also be applied seamlessly to pipe and cistern problems as well as relative work-rate concepts.