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Rakesh starts from Point A and drives 21 km towards the west. He then takes a left turn, drives 23 km, turns left and drives 27 km. He then takes a left turn and drives 28 km. He takes a final left turn, drives 6 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again? (All turns are 90┬░ turns only unless specified.)
2 km to the south
3 km to the south
4 km to the south
5 km to the south
5 km to the south
Track net displacements along axes: West/East as X-axis and North/South as Y-axis. Net X = -21 + 27 - 6 = 0; Net Y = -23 + 28 = +5 (5 km North of A). To return to A from P, move 5 km South.
Track net displacements along axes: West/East as X-axis and North/South as Y-axis. Net X = -21 + 27 - 6 = 0; Net Y = -23 + 28 = +5 (5 km North of A). To return to A from P, move 5 km South.
Step 1: Track East-West (X-axis) Displacements
Starting at Point A (0,0):
Step 2: Track North-South (Y-axis) Displacements
Starting at Point A (0,0):
Step 3: Determine Return Direction and Distance from P to A
Point P is located at (0, +5), which means P is 5 km North of Point A. To travel from Point P back to Point A, Rakesh must head 5 km in the South direction.
A: Incorrect displacement magnitude (2 km instead of 5 km). B: Incorrect displacement magnitude (3 km instead of 5 km). C: Incorrect displacement magnitude (4 km instead of 5 km).
D is correct because Point P is 5 km North of Point A, so Rakesh must drive 5 km to the south to return to Point A.
Always pay attention to whether the question asks for the position of the final point relative to the start point, or the direction needed to return to the starting point from the final point (they are opposite in direction).