Analyze the condition

We need to find a pattern: (Symbol) followed by (Number) followed by (Number).

Examine the series

Series: 7, 9, @, #, 2, *, £, 4, 6, $, 8, &, 5, 3, &, %, Ω, 1. Triplet search: @ is followed by # (not a number); # is followed by 2 (number) but preceded by @ (symbol) - wait, # is a symbol. Let us check: @ (Symbol) # (Symbol). Next, # (Symbol)₂ (Number) * (Symbol). Next, 2 (Number) * (Symbol) £ (Symbol). Next, * (Symbol) £ (Symbol)₄ (Number). Next, £ (Symbol)₄ (Number)₆ (Number). Here, 4 is preceded by £ (Symbol) and followed by 6 (Number). This fits the criteria: Symbol (£) → Number (4) → Number (6).

Re-evaluating the series string

Re-reading the sequence: 7, 9, @, #, 2, *, £, 4, 6, , 8, &, 5, 3, &, \%, Ω, 1. \text{Sequence check}: @#2 (\text{Symbol}-\text{Symbol}-\text{Number}), #2* (\text{Symbol}-\text{Number}-\text{Symbol}), 2*£ (\text{Number}-\text{Symbol}-\text{Symbol}), *£4 (\text{Symbol}-\text{Symbol}-\text{Number}), £46 (\text{Symbol}-\text{Number}-\text{Number}) - YES, this is one. 46 (Number-Number-Symbol), 6$8 (\text{Number}-\text{Symbol}-\text{Number}),$8& (Symbol-Number-Symbol), 8&5 (Number-Symbol-Number), &53 (Symbol-Number-Number) - YES, this is two. 53& (Number-Number-Symbol), 3&% (Number-Symbol-Symbol), &%Ω (Symbol-Symbol-Symbol), %Ω1 (Symbol-Symbol-Number). Total count is 2.