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A car covers four successive 3 km stretches at speeds of 10 km/h, 20 km/h, 30 km/h and 60 km/h, respectively. Its average speed over this distance is:
30 km/h
15 km/h
20 km/h
25 km/h
20 km/h
Since the distances are equal, average speed for equal distances is the harmonic mean of the speeds: vavg=v11+v21+v31+v41n.
Four successive 3 km stretches. Speeds: v1 = 10\text{ km/h},$$v_2 = 20\text{ km/h},$$v_3 = 30\text{ km/h},$$v_4 = 60 km/h
vavg=Total TimeTotal Distance=v1d+v2d+v3d+v4d4d
Since the distances are equal, average speed for equal distances is the harmonic mean of the speeds: vavg=v11+v21+v31+v41n.
Do not simply take the arithmetic mean of the speeds ((10+20+30+60)/4=30), because average speed is total distance divided by total time.
Step 1: Identify distance and speeds for each stretch
The total distance is divided into four equal stretches of d=3 km each. The respective speeds are v1=10 km/h, v2=20 km/h, v3=30 km/h, and v4=60 km/h.
d=3 km,v1=10,v2=20,v3=30,v4=60
Step 2: Calculate the time taken for each stretch
Time taken for each stretch is given by Time=SpeedDistance. Thus, t1=103, t2=203, t3=303=101, and t4=603=201.
t1=103,t2=203,t3=303,t4=603
Step 3: Find total distance and total time
Total distance = 3+3+3+3=12 km. Total time = 103+203+303+603=6018+9+6+3=6036=53 hours.
Total Distance=12 km,Total Time=6036=53 hours
Step 4: Calculate average speed
Applying the average speed formula: vavg=Total TimeTotal Distance=3/512=12×35=20 km/h.
vavg=5312=20 km/h
C is correct because the total distance of 12 km divided by the total time of 3/5 hours yields an average speed of 20 km/h.