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Anil spends 40% of his income on rent and 40% of the remaining income on medicines. If he saves ₹7,200 every month, then his monthly income is:
₹22,000
₹20,000
₹36,000
₹25,000
₹20,000
Use successive percentage multipliers: Savings = Income ×10060×10060. Solve for Income directly.
Anil spends 40% of his income on rent, 40% of the remaining income on medicines, and saves ₹7,200 every month.
Income×(1−10040)×(1−10040)=Savings
Use successive percentage multipliers: Savings = Income ×10060×10060. Solve for Income directly.
Adding percentages directly (40%+40%=80% spent, leaving 20%) instead of calculating the remaining amount successively.
Assume Total Income
Let Anil's total monthly income be x.
Total Income=x
Calculate Remaining Income after Rent
He spends 40% of his income on rent. The remaining income is 60% of x.
Remaining1=x×(1−10040)=0.60x
Calculate Remaining Income after Medicines
He spends 40% of the remaining income on medicines. The amount left is 60% of 0.60x, which represents his savings.
Savings=0.60x×(1−10040)=0.60×0.60x=0.36x
Equate Savings and Solve for Income
Given that his monthly savings are ₹7,200, we set 0.36x=7200. Solving for x: x=0.367200=20,000
x=0.367200=20,000
B is correct because calculating successively, 36% of Anil's total income equals ₹7,200, giving a monthly income of ₹20,000.
Successive percentage problems are common in profit & loss, population growth, and successive discounts in commercial arithmetic.