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Simplify: (1−sec2θ)(1−sinθ)(1+sinθ)(1+cot2θ).
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Use standard trigonometric identities like (1−sinθ)(1+sinθ)=cos2θ and 1−sec2θ=−tan2θ to quickly transform and cancel terms.
The given expression is: (1−sec2θ)(1−sinθ)(1+sinθ)(1+cot2θ)
sec2θ−1=tan2θ,(1−sinθ)(1+sinθ)=1−sin2θ=cos2θ,1+cot2θ=csc2θ
Use standard trigonometric identities like (1−sinθ)(1+sinθ)=cos2θ and 1−sec2θ=−tan2θ to quickly transform and cancel terms.
Forgetting the negative sign when converting 1−sec2θ to −tan2θ.
Step 1: Simplify the first factor
We know that sec2θ−1=tan2θ, so 1−sec2θ=−tan2θ.
1−sec2θ=−tan2θ
Step 2: Simplify the second and third factors
Using the algebraic identity (a−b)(a+b)=a2−b2, we get (1−sinθ)(1+sinθ)=1−sin2θ=cos2θ.
(1−sinθ)(1+sinθ)=cos2θ
Step 3: Simplify the fourth factor
Using the Pythagorean identity for cosecant and cotangent, 1+cot2θ=csc2θ.
1+cot2θ=csc2θ
Step 4: Combine all simplified terms
Substitute all parts back into the expression: (−tan2θ)⋅(cos2θ)⋅(csc2θ). Express tan2θ as cos2θsin2θ and csc2θ as sin2θ1.
−(cos2θsin2θ)⋅(cos2θ)⋅(sin2θ1)=−1
B is correct because simplifying the expression using fundamental trigonometric identities results in -1.
Mastering fundamental trigonometric identities allows for quick reductions of complex algebraic expressions in calculus and trigonometry sections.