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P is 30% more efficient than Q. How much time will they, working together, take to complete a job that P alone could have done in 23 days?
11 days
13 days
20173тАЛ ┬аdays
10 days
13 days
Convert efficiency percentage to a ratio, find Q's days, find total work as LCM, then divide by combined efficiency.
P is 30% more efficient than Q. P alone can complete the job in 23 days.
Time=EfficiencyTotal┬аWorkтАЛ
Convert efficiency percentage to a ratio, find Q's days, find total work as LCM, then divide by combined efficiency.
Adding efficiencies directly without converting to the proper work ratio or taking reciprocal of time.
Step 1: Determine the efficiency ratio of P and Q
Since P is 30% more efficient than Q, if Q's efficiency is 100, P's efficiency is 130. Thus, the ratio of efficiencies of P:Q=13:10.
EPтАЛ:EQтАЛ=13:10
Step 2: Find the time taken by Q alone
Time is inversely proportional to efficiency, so the time ratio of P:Q=10:13. Given P takes 23 days, let 10x=23тЯ╣x=2.3. Therefore, Q takes 13├Ч2.3=29.9 days.
TQтАЛ=23├Ч1013тАЛ=29.9┬аdays
Step 3: Calculate combined time taken by P and Q working together
Using the formula for combined work time: Time=TPтАЛ+TQтАЛTPтАЛ├ЧTQтАЛтАЛ=23+29.923├Ч29.9тАЛ=52.9687.7тАЛ=13 days.
TimetogetherтАЛ=23+29.923├Ч29.9тАЛ=13┬аdays
B is correct because working together, P and Q complete the job in 13 days.
Efficiency ratios are foundational in pipes and cisterns as well as speed, time, and distance problems involving engines or workers.