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A shopkeeper, on selling a pan for ₹10, loses 111 of what it cost him. The cost price of a pan is:
₹10
₹11
₹9
₹12
₹11
Since Loss = 111 of CP, SP = CP - Loss = 1−111=1110 of CP. Therefore, 1110×CP=10, giving CP = ₹11.
Selling Price (SP) = ₹10, Loss = 111 of Cost Price (CP)
Loss=CP−SP
Since Loss = 111 of CP, SP = CP - Loss = 1−111=1110 of CP. Therefore, 1110×CP=10, giving CP = ₹11.
Students often calculate 111 of the Selling Price (₹10) instead of the Cost Price, leading to an incorrect decimal answer.
Define the relationship between SP, CP, and Loss
Let the cost price of the pan be CP. According to the problem, the shopkeeper loses 111 of its cost price.
Loss=111×CP
Apply Selling Price formula
We know that Selling Price is given by SP=CP−Loss. Substituting the value of Loss:
SP=CP−111CP=1110CP
Substitute SP and solve for CP
Given that SP=₹10, we set up the equation 1110×CP=10. Multiplying both sides by 1011 gives:
CP=10×1011=11
B is correct because solving the equation 1110×CP=10 yields a cost price of ₹11.
Fractional loss and profit relations are frequently used in quantitative aptitude to quickly find base values without using percentage conversions.