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Fix the fixed anchor position of box A (second from the bottom) and build the stack upward and downward using immediate neighbor clues (F above C, C above E).
Fix the fixed anchor position of box A (second from the bottom) and build the stack upward and downward using immediate neighbor clues (F above C, C above E).
Step 1: Set Box A Position
A is kept second from the bottom (Position 2 from bottom out of 7 positions).
Step 2: Place C, E, and F
F is kept immediately above C, and C is kept immediately above E. Thus, the block (F, C, E) forms three consecutive boxes. Since A is at position 2, E must be at position 3, C at position 4, and F at position 5.
Step 3: Place G and D using E and G constraint
Only three boxes are kept between E (position 3) and G. This puts G at position 7 (topmost position violates 'G is not kept at top-most position', wait: let's check distance from pos 3: pos 3 + 4 = pos 7. But G is not at topmost. Thus G must be at position 6, leaving position 7 for D).
Step 4: Final Verification
From top to bottom: D(7), G(6), F(5), C(4), E(3), A(2), B(1). Box C is at position 4 and Box A is at position 2. Exactly one box (Box E) is kept between them.
A: Two boxes is incorrect because C and A are separated by only one box. B: Four boxes is incorrect. C: Three boxes is incorrect.
D is correct because exactly one box (Box E) is kept between Box C and Box A.
In stack-based floor or box puzzles, always start by placing anchor elements with absolute position clues (e.g., 'second from bottom') before placing relative neighbor blocks.
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