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On the basis of the English alphabet order, three of the following four letter-pair combinations are alike in a certain way and thus form a group. Which combination does not belong to that group? (Note: The odd pair is not selected based on the number of vowels/consonants or their positions within the letter group.) ZI-UD
BK-VE
TC-NW
EN-YH
None of the above
BK-VE
Convert each letter to its alphabetical position. Check the difference between the first and second letters, and the third and fourth letters of each pair to find the common pattern.
Convert each letter to its alphabetical position. Check the difference between the first and second letters, and the third and fourth letters of each pair to find the common pattern.
Analyze Option A (ZI-UD)
Z is 26 and I is 9 (26 - 17 = 9). U is 21 and D is 4 (21 - 17 = 4). Both letter shifts are -17.
Analyze Option B (BK-VE)
B is 2 and K is 11 (2 + 9 = 11). V is 22 and E is 5 (22 - 17 = 5). Mixed pattern (+9 and -17).
Analyze Option C (TC-NW)
T is 20 and C is 3 (20 - 17 = 3). N is 14 and W is 23 (14 + 9 = 23). Mixed pattern (-17 and +9).
Conclusion
Option A follows a uniform -17 backward shift for both letter pairs, whereas options B, C, and D do not share this consistent uniform shift.
B: Has mixed shifts (+9, -17). C: Has mixed shifts (-17, +9). D: Has mixed shifts (+10, -17).
A is correct because ZI-UD is the only letter-cluster pair where both pairs of letters follow a consistent backward shift of 17 positions in the English alphabet.
For letter-cluster classification questions, always convert letters to numerical positions and check the difference between consecutive pairs first.
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