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Among the numbers from 1 to 70 (both inclusive), what percentage of numbers have the unit digit as 1 or 7?
14
20
1
10
1
In any block of 10 consecutive integers, exactly 2 numbers end in 1 or 7 (e.g., 1 and 7, 11 and 17). For 70 numbers, there are 7 such blocks, giving 7 ├Ч 2 = 14 favorable numbers.
Range of numbers from 1 to 70 both included
Percentage=Total┬аcountFavorable┬аcountтАЛ├Ч100
In any block of 10 consecutive integers, exactly 2 numbers end in 1 or 7 (e.g., 1 and 7, 11 and 17). For 70 numbers, there are 7 such blocks, giving 7 ├Ч 2 = 14 favorable numbers.
Confusing '1 to 70' with '0 to 70' or miscalculating the number of occurrences of digits 1 and 7 in the units place across 7 decades.
Step 1: Identify the total number of integers
The integers are from 1 to 70 inclusive, so the total count of numbers is 70.
Total┬аnumbers=70
Step 2: Count numbers with unit digit 1 or 7
In every group of 10 numbers (e.g., 1-10, 11-20), exactly two numbers have 1 or 7 in their unit's place (e.g., 1, 7; 11, 17; etc.). Across 7 blocks of 10 from 1 to 70, the number of such integers is 7├Ч2=14.
Favorable┬аcount=7├Ч2=14
Step 3: Calculate the percentage
Divide the favorable count by the total count and multiply by 100: 7014тАЛ├Ч100=51тАЛ├Ч100=20%
Percentage=7014тАЛ├Ч100=20%
C is correct because exactly 14 numbers out of 70 have a unit's digit of 1 or 7, yielding exactly 20%.
Similar unit digit counting techniques are frequently used in number theory and divisibility tests in RRB competitive exams.