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Two numbers are in the ratio 3:2. Their LCM and HCF are 24 and 4, respectively. The greater of the two numbers is:
10
8
12
14
12
Since the numbers are 3x and 2x, their HCF is x. Given HCF =4, so x=4. The numbers are 3(4)=12 and 2(4)=8. The greater is 12.
Ratio of two numbers = 3:2, LCM = 24, HCF = 4
LCM=HCF├Чa├Чb
Since the numbers are 3x and 2x, their HCF is x. Given HCF =4, so x=4. The numbers are 3(4)=12 and 2(4)=8. The greater is 12.
Many students try to use the formula LCM├ЧHCF=Product┬аof┬аnumbers without realizing the ratio a:b already defines the numbers in terms of HCF.
Define the numbers
Since the ratio of the two numbers is 3:2, let the numbers be 3x and 2x, where x is the HCF.
Number1тАЛ=3x,Number2тАЛ=2x
Use the given HCF
The problem states the HCF is 4. Thus, x=4.
x=4
Calculate the values
Substitute x=4 back into the expressions for the two numbers.
3├Ч4=12,2├Ч4=8
Identify the greater number
Comparing 12 and 8, the greater number is 12.
12>8
C is correct because the numbers are 12 and 8, making 12 the greater value.
Always remember that any two numbers can be expressed as HтЛЕa and HтЛЕb, where H is the HCF and a,b are co-prime integers forming the ratio.