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Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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A dishonest shopkeeper pretends to sell his goods at cost price. However, he uses a false weight on which 984 gm is written, but actually weighs lesser. Using this false weight, the shopkeeper makes a gain of 23%. The actual measure of the weight used is:
935 gm
800 gm
850 gm
900 gm
800 gm
Use the formula: False Weight=1+Gain%Printed Weight which gives False Weight=1.23984=800 gm.
Printed weight = 984 gm, Gain percentage = 23%
Gain%=False WeightTrue Weight−False Weight×100
Use the formula: False Weight=1+Gain%Printed Weight which gives False Weight=1.23984=800 gm.
Many students subtract the gain percentage directly from 984 gm or calculate 23% of 984 gm incorrectly, which leads to wrong options.
Step 1: Understand the relationship between false weight and gain
When a shopkeeper sells goods using a false weight and pretends to sell at cost price, the gain percentage is obtained by the ratio of error to the actual weight used.
Gain%=Actual WeightPrinted Weight−Actual Weight×100
Step 2: Set up the equation using given values
Let the actual weight be x gm. The shopkeeper gains 23% using the false weight of 984 gm.
23=x984−x×100
Step 3: Solve for the actual weight x
Rearranging the equation: x984−x=0.23⟹984−x=0.23x⟹1.23x=984
x=1.23984=800 gm
B is correct because the actual measure of the weight used calculated from the 23% gain and 984 gm printed weight is 800 gm.
Questions involving dishonest merchants frequently appear in quantitative aptitude tests. Always relate the perceived quantity to the actual quantity handled to find the correct ratio.
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