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5118 is divisible by which of the following?
6
7
8
5
6
Check divisibility by 6 by verifying both divisibility by 2 and divisibility by 3. Since 5118 ends in 8 (even) and the sum of digits 5+1+1+8=15 is divisible by 3, 5118 is divisible by 6.
Number = 5118
5118(mod6)=0,5118(mod7)=0
Check divisibility by 6 by verifying both divisibility by 2 and divisibility by 3. Since 5118 ends in 8 (even) and the sum of digits 5+1+1+8=15 is divisible by 3, 5118 is divisible by 6.
Students often test division by 7 manually without checking divisibility by 2 and 3 first, or they confuse divisibility rules for 7.
Step 1: Check Divisibility by 2
A number is divisible by 2 if its last digit is even. The last digit of 5118 is 8, which is even.
5118÷2=2559
Step 2: Check Divisibility by 3
A number is divisible by 3 if the sum of its digits is divisible by 3. Sum of digits = 5+1+1+8=15, which is divisible by 3.
15÷3=5
Step 3: Check Divisibility by 6
Since 5118 is divisible by both 2 and 3, it is divisible by 6.
5118÷6=853
A is correct because 5118 is divisible by 6, yielding an integer quotient of 853.
Divisibility rules for composite numbers like 6, 12, 15, and 18 can always be broken down into checking coprime factors.
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