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The diameters of two concentric circles are 34 cm and 50 cm. A straight line, CAPF, intersects the larger circle at points C and F and intersects the smaller circle at points A and P. If AP=16 cm, find the length of CF.
30 cm
34 cm
40 cm
48 cm
48 cm
Use the property that a line segment intersecting two concentric circles is bisected by the radius of the smaller circle perpendicular to it. The distance from the center to the chord is d=r2−82.
Diameter of larger circle = 50 cm, Diameter of smaller circle = 34 cm. Segment AP on the smaller circle = 16 cm. Line CAPF intersects both circles.
R2=r2+d2, CF=2×R2−d2
Use the property that a line segment intersecting two concentric circles is bisected by the radius of the smaller circle perpendicular to it. The distance from the center to the chord is d=r2−82.
Using diameters (34 and 50) instead of radii (17 and 25) in the Pythagorean theorem calculation.
Calculate Radii
Radii are half the diameters: R=50/2=25 cm and r=34/2=17 cm.
R=25,r=17
Find distance from center to chord
The line segment AP is a chord of the smaller circle with length 16 cm. The perpendicular distance d from the center to this chord bisects it (8 cm) and forms a right triangle with radius r.
d=172−82=289−64=15
Calculate length of CF
The distance d is also the distance from the center to chord CF of the larger circle. Using the Pythagorean theorem for the larger circle: CF/2=R2−d2.
CF=2×252−152=2×20=40
D is correct because the chord length is calculated as 40 cm using the property of perpendicular bisectors in concentric circles.
This property is essential in Coordinate Geometry for finding intersection points of lines and circles.