Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
The value of 13−82+(436)2−0+2×5= ————
28
27
37
38
28
Evaluate the powers and brackets first, then solve the multiplication before adding and subtracting left-to-right to avoid errors.
The expression provided is 13−82+(436)2−0+2×5.
BODMAS=Brackets,Orders,Division,Multiplication,Addition,Subtraction
Evaluate the powers and brackets first, then solve the multiplication before adding and subtracting left-to-right to avoid errors.
Students often make mistakes by performing subtraction before multiplication or by evaluating 82 incorrectly as 16 instead of 64.
Simplify terms using BODMAS
First, evaluate the powers and the expression inside the parentheses: 13=1, 82=64, and (436)=9.
1−64+92−0+2×5
Evaluate the square and multiplication
Next, solve the square 92=81 and the multiplication 2×5=10.
1−64+81−0+10
Final addition and subtraction
Perform the operations from left to right: 1−64=−63, then −63+81=18, and finally 18+10=28.
28
A is correct because the result of the expression 13−82+(436)2−0+2×5 is calculated to be 28.
The BODMAS rule is essential for all simplification questions in competitive exams; always prioritize brackets and exponents before arithmetic operators.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants