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A rectangular field 50 meters long and 42 meters broad contains a rectangular lawn inside it surrounded by a gravel path of uniform width. If the width of the path is 6 m, then the area of the path is
480m2
720m2
240m2
960m2
960m2
Calculate outer area (5042 = 2100). Subtract path width from both sides to get inner dimensions (50-12=38, 42-12=30). Inner area = 3830 = 1140. Path area = 2100 - 1140 = 960.
Field length = 50 m, field breadth = 42 m, path width = 6 m
Area=AreaouterтАЛтИТAreainnerтАЛ
Calculate outer area (5042 = 2100). Subtract path width from both sides to get inner dimensions (50-12=38, 42-12=30). Inner area = 3830 = 1140. Path area = 2100 - 1140 = 960.
Subtracting 6m only once from each dimension instead of twice (once for each side of the field).
Calculate outer area
The outer rectangle is the field itself. AreaouterтАЛ=length├Чbreadth=50├Ч42
AreaouterтАЛ=2100m2
Calculate inner dimensions
Since the path of width 6 m is inside, we subtract twice the width from both length and breadth: lengthinnerтАЛ=50тИТ(2├Ч6)=38, breadthinnerтАЛ=42тИТ(2├Ч6)=30
38m,30m
Calculate inner area
The area of the lawn inside is: AreainnerтАЛ=38├Ч30
AreainnerтАЛ=1140m2
Calculate path area
The area of the gravel path is the difference between the outer and inner areas: Area=2100тИТ1140
Area=960m2
D is correct because the difference between the field area (2100m2) and the lawn area (1140m2) is 960m2.
This concept is frequently tested in 'Mensuration' chapters of SSC/Railway exams; always remember that a uniform path inside a shape subtracts 2x the width from each dimension.