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The value of sin2θ+cos2θ−(sec2θ−tan2θ)+cotθsinθ+cosθ is ________.
2cosθ
−1
sec2θ
0
2cosθ
Directly substitute trigonometric identities into the expression: 1 - 1 + (cos θ / sin θ) * sin θ + cos θ = 0 + cos θ + cos θ = 2 cos θ.
Expression to evaluate: sin² θ + cos² θ - (sec² θ - tan² θ) + cot θ sin θ + cos θ
sin2θ+cos2θ=1, sec2θ−tan2θ=1, cotθ=sinθcosθ
Directly substitute trigonometric identities into the expression: 1 - 1 + (cos θ / sin θ) * sin θ + cos θ = 0 + cos θ + cos θ = 2 cos θ.
Students often struggle with the cot θ * sin θ term; remember that cot θ = cos θ / sin θ, so cot θ * sin θ simplifies to just cos θ.
Simplify using fundamental identities
We know that sin2θ+cos2θ=1 and sec2θ−tan2θ=1. Substituting these into the original expression.
1−1+cotθsinθ+cosθ
Convert cotangent to sine and cosine
Substitute cotθ=sinθcosθ into the expression and simplify the product.
0+(sinθcosθ)sinθ+cosθ
Final addition
Canceling sinθ in the term, we get cosθ+cosθ=2cosθ.
2cosθ
A is correct because the entire expression simplifies algebraically to 2 cos θ using trigonometric identities.
This type of simplification frequently appears in SSC and railway exams; always look to reduce expressions using the three primary Pythagorean identities first.