Join 60,000+ competitive exam aspirants
The present age of a teacher is 121тАЛ times the sum of the present ages of his two students. Six years hence, the ratio of his age to the sum of the ages of both the students will be 6:5. The present age of the teacher is:
42 years
45 years
50 years
36 years
42 years
Use the ratio 6:5 for the future ages. Since the teacher is 6 years older than the students (6 units vs 5 units), 1 unit difference corresponds to the actual age adjustment. 6 units = 48, 5 units = 40. Subtracting the 6 years elapsed gives T = 42.
Present teacher age T is 1.5 times the sum of two students' ages S. After 6 years, teacher's age (T+6) to the sum of students' ages (S+12) is 6:5.
T=23тАЛS,S+12T+6тАЛ=56тАЛ
Use the ratio 6:5 for the future ages. Since the teacher is 6 years older than the students (6 units vs 5 units), 1 unit difference corresponds to the actual age adjustment. 6 units = 48, 5 units = 40. Subtracting the 6 years elapsed gives T = 42.
Students often add 6 years only to the sum of the students' ages (S+6) instead of the correct (S+6+6)=S+12 because two students each age by 6 years.
Define variables
Let the sum of the two students' present ages be S and the teacher's age be T. Given T=1.5S, we can write T=23тАЛS.
T=23тАЛS
Future age relationship
After 6 years, the teacher's age is T+6. Each of the two students also ages by 6 years, so the new sum of students' ages is S+6+6=S+12.
S+12T+6тАЛ=56тАЛ
Solve the system
Substitute T=23тАЛS into the ratio equation: 5(1.5S+6)=6(S+12). Expanding gives 7.5S+30=6S+72, which simplifies to 1.5S=42, or S=28.
1.5S=42тЯ╣S=28
Calculate Teacher's age
Using T=1.5S, we find T=1.5├Ч28=42.
T=42
A is correct because the calculation T=1.5├Ч28 yields 42 years.
Always remember that if multiple people are involved (like two students), the age increment for the sum of their ages is the number of years times the count of people.