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The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The median of the data is:
3
0
1
2
3
Arrange the 10 numbers in ascending order. Since 10 is even, the median is the average of the 5th and 6th terms.
Wickets taken by a bowler in 10 matches: 2, 6, 4, 5, 0, 3, 1, 3, 2, 3
Median=2(2n)th observation+(2n+1)th observation
Arrange the 10 numbers in ascending order. Since 10 is even, the median is the average of the 5th and 6th terms.
Forgetting to sort the data in ascending order before finding the median or picking the middle number without averaging for even-sized data sets.
Sort the data
List the given wickets in ascending order: 0, 1, 2, 2, 3, 3, 3, 4, 5, 6.
0,1,2,2,3,3,3,4,5,6
Identify number of terms
The number of matches n is 10, which is an even number.
n=10
Apply Median formula
For even n, the median is the average of the 5th and 6th observations. The 5th term is 3 and the 6th term is 3.
Median=23+3=3
A is correct because the average of the 5th and 6th terms in the sorted sequence [0, 1, 2, 2, 3, 3, 3, 4, 5, 6] is 3.
This concept is foundational for calculating Mean, Median, and Mode in grouped and ungrouped data, which is a common topic in railway recruitment exams.
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