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If each vowel in the word MAJORITY is changed to the letter following it in the English alphabetical order and each consonant is changed to the letter preceding it in the English alphabetical order, then how many letters are common between the original word and the group of letters thus formed?
3
2
4
1
2
Identify vowels (A, E, I, O, U) and consonants in the word, then apply +1 to vowels and -1 to consonants. Compare the new sequence with the original.
Identify vowels (A, E, I, O, U) and consonants in the word, then apply +1 to vowels and -1 to consonants. Compare the new sequence with the original.
Categorize Letters
Word: MAJORITY. M (Consonant), A (Vowel), J (Consonant), O (Vowel), R (Consonant), I (Vowel), T (Consonant), Y (Consonant).
Apply Transformation Rules
Vowel тЖТ Next letter (+1), Consonant тЖТ Previous letter (-1). M(-1)=L, A(+1)=B, J(-1)=I, O(+1)=P, R(-1)=Q, I(+1)=J, T(-1)=S, Y(-1)=X.
Comparison
Original letters: {M, A, J, O, R, I, T, Y}. Transformed letters: {L, B, I, P, Q, J, S, X}. Only the letter 'I' appears in both sets.
A: 3 is incorrect because only 1 letter is common. C: 2 is incorrect because there is only 1 match. D: 4 is incorrect because there is only 1 match.
B is correct because the transformation results in L, B, I, P, Q, J, S, X and the only letter present in both the original word and the transformed group is I, making the count 1.
Always verify if the question mentions 'English alphabetical order' for cyclical shifts (like Z тЖТ A); here it is a simple sequence shift.
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