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One year ago, the ratio of the ages of Sara and Dipti was 3:4, respectively. Four years hence, this ratio would become 4:5. The present age of Sara is:
12 years
19 years
16 years
15 years
16 years
Observe the difference in ratios. The ratio changes from 3:4 to 4:5. Both sides increase by 1 part. This 1 part corresponds to the time gap of 5 years (1 year ago to 4 years hence). Thus, 1 unit = 5 years. One year ago, Sara was 3 units = 15 years. Her present age is 15 + 1 = 16.
Ratio of ages one year ago was 3:4. Ratio of ages four years hence will be 4:5.
4x+1+k3x+1+kтАЛ=n2тАЛn1тАЛтАЛ
Observe the difference in ratios. The ratio changes from 3:4 to 4:5. Both sides increase by 1 part. This 1 part corresponds to the time gap of 5 years (1 year ago to 4 years hence). Thus, 1 unit = 5 years. One year ago, Sara was 3 units = 15 years. Her present age is 15 + 1 = 16.
Confusing the time interval: the interval between '1 year ago' and '4 years hence' is 5 years, not 3 or 4.
Define ages based on ratio
Let the ages of Sara and Dipti one year ago be 3x and 4x. Their present ages are 3x+1 and 4x+1.
SarapastтАЛ=3x,DiptipastтАЛ=4x
Set up equation for future ages
Four years hence, their ages will be (3x+1)+4=3x+5 and (4x+1)+4=4x+5. Given the ratio is 4:5, we equate:
4x+53x+5тАЛ=54тАЛ
Solve for x
Cross-multiplying: 5(3x+5)=4(4x+5)тЗТ15x+25=16x+20. Rearranging gives x=5.
x=5
Calculate present age of Sara
Sara's age one year ago was 3x=3(5)=15. Adding 1 year gives the current age.
15+1=16
C is correct because the calculated present age of Sara is 16 years.
This 'Ratio Difference' method is universally applicable to any problem involving a change in two quantities over the same time interval (e.g., mixtures, investments).