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Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
TP - OI
KO - WA
BX - WQ
AW - VP
KO - WA
Look for the difference between the alphabetical positions of letters in each pair. If the difference is consistent for three pairs, the one that deviates is the answer.
Look for the difference between the alphabetical positions of letters in each pair. If the difference is consistent for three pairs, the one that deviates is the answer.
Analyze Position Values
Convert letters to their A=1, B=2... Z=26 positions: A=1, W=23; B=2, X=24; K=11, O=15; T=20, P=16.
Calculate Differences
A(1) to W(23) is -4 (1-4 = -3, +26 = 23). B(2) to X(24) is -4 (2-4 = -2, +26 = 24). T(20) to P(16) is -4 (20-4 = 16). K(11) to O(15) is +4 (11+4 = 15).
Identify Odd One Out
Pairs TP, BX, and AW have a position shift of -4. The pair KO has a shift of +4.
A: Follows -4 shift; C: Follows -4 shift; D: Follows -4 shift.
B is correct because the pair KO has a shift of +4 while all other pairs follow a shift of -4.
When dealing with letter-cluster pairs, always check the difference between values (Position of Letter 2 - Position of Letter 1). A, B, C or D often hide a cyclic -N or +N pattern.
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