Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
Evaluate the given expression. 36−[12+(3×10÷2)]
2
1
10
9
9
Focus on the innermost parenthesis first: 10 ÷ 2 = 5, then 3 × 5 = 15, add 12 to get 27, finally subtract from 36.
Expression: 36 - [12 + (3 × 10 ÷ 2)]
BODMAS=Brackets,Orders,Division,Multiplication,Addition,Subtraction
Focus on the innermost parenthesis first: 10 ÷ 2 = 5, then 3 × 5 = 15, add 12 to get 27, finally subtract from 36.
Performing addition before the multiplication inside the bracket (e.g., 3 × 10 = 30, then 30 ÷ 2 = 15). Always follow Multiplication before Addition within brackets as per BODMAS.
Solve innermost parentheses
Perform division inside the parentheses: 10 ÷ 2 = 5. The expression becomes: 36 - [12 + (3 × 5)].
10÷2=5
Complete multiplication inside parentheses
Multiply 3 by 5: 3 × 5 = 15. The expression becomes: 36 - [12 + 15].
3×5=15
Simplify square brackets
Add 12 and 15: 12 + 15 = 27. The expression becomes: 36 - 27.
12+15=27
Final subtraction
Subtract 27 from 36: 36 - 27 = 9.
36−27=9
D is correct because 36 - [12 + (3 × 5)] = 36 - [12 + 15] = 36 - 27 = 9.
This is a foundational concept in simplification. Mastering BODMAS is essential for solving complex algebraic expressions and quantitative aptitude problems in RRB and other competitive exams.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants