Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
The average of the first 50 natural numbers is:
25
25.5
21.25
12.25
25.5
For the first 'n' natural numbers, the average is always (n + 1) / 2. Here, n = 50, so simply calculate (50 + 1) / 2 = 25.5.
We need to find the average of the first 50 natural numbers.
Average=2n+1тАЛ
For the first 'n' natural numbers, the average is always (n + 1) / 2. Here, n = 50, so simply calculate (50 + 1) / 2 = 25.5.
Do not confuse the average of the first 50 natural numbers with the sum of the first 50 natural numbers, which is (n * (n + 1)) / 2.
Identify the set of numbers
The first 50 natural numbers are 1, 2, 3, ..., 50.
n=50
Apply the average formula
The average of the first 'n' natural numbers is calculated using the formula: Average=2n+1тАЛ
Average=2n+1тАЛ
Calculate the final result
Substitute n=50 into the formula: Average=250+1тАЛ=251тАЛ=25.5
Average=25.5
B is correct because the average of the first n natural numbers is given by 2n+1тАЛ, and for n=50, 250+1тАЛ=25.5.
This concept is a special case of the average of an Arithmetic Progression, where the average is always the mean of the first and last term, i.e., (First + Last) / 2.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants