Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
The sum of three consecutive multiples of 9 is 2457, find the smallest one.
999
990
810
819
810
Since the numbers are in an arithmetic progression, the middle number is the average: 2457├╖3=819. The smallest number is 819тИТ9=810.
Sum of three consecutive multiples of 9 is 2457.
n+(n+9)+(n+18)=2457
Since the numbers are in an arithmetic progression, the middle number is the average: 2457├╖3=819. The smallest number is 819тИТ9=810.
Students often assume the numbers are x,x+1,x+2 instead of multiples of 9 (n,n+9,n+18), leading to incorrect values.
Define the terms
Let the three consecutive multiples of 9 be n, n+9, and n+18.
n,n+9,n+18
Set up the equation
The sum of these three multiples is given as 2457. Therefore, we sum them and set the result to 2457.
n+(n+9)+(n+18)=2457
Solve for n
Combine like terms: 3n+27=2457. Subtract 27 from both sides: 3n=2430. Finally, divide by 3.
n=32430тАЛ=810
C is correct because the calculated smallest multiple of 9 is 810.
For any odd number of consecutive terms in an arithmetic progression, the average of the terms is always equal to the median (middle) term.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants