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Simplify the following expression: 1−sinθcosθ+cosθ1−sinθ
2secθ
2cosθ
2sinθ
1+2sinθ
2secθ
Plug in a convenient angle like θ=0°. The expression becomes 11+11=2. Checking the options at θ=0°: A gives 2sec(0)=2, B gives 2cos(0)=2, C gives 2sin(0)=0, D gives 1+0=1. Eliminating via θ=60° confirms A.
An expression containing trigonometric functions:1−sinθcosθ +cosθ1−sinθ.
sin2θ+cos2θ=1, secθ=cosθ1
Plug in a convenient angle like θ=0°. The expression becomes 11+11=2. Checking the options at θ=0°: A gives 2sec(0)=2, B gives 2cos(0)=2, C gives 2sin(0)=0, D gives 1+0=1. Eliminating via θ=60° confirms A.
Students often struggle with the conjugate multiplication or common denominator approach, leading to sign errors when expanding the numerator (1−sinθ)2.
Find a common denominator
To add the fractions, use the common denominator (cosθ)(1−sinθ).
cosθ(1−sinθ)cos2θ+(1−sinθ)2
Expand the numerator
Expand the squared term (1−sinθ)2=1−2sinθ+sin2θ.
cosθ(1−sinθ)cos2θ+1−2sinθ+sin2θ
Simplify using identities
Substitute sin2θ+cos2θ=1 into the numerator: 1+1−2sinθ=2(1−sinθ).
cosθ(1−sinθ)2(1−sinθ)
Final reduction
Cancel the common term (1−sinθ) to get cosθ2, which is 2secθ.
cosθ2=2secθ
A is correct because the algebraic simplification of the expression results in 2secθ.
This type of simplification frequently appears in calculus where expressions are rewritten to make integration easier (e.g., rewriting trigonometric quotients as secant or tangent).