Set up linear equations

Let the cost of a table be $T$ and the cost of a chair be $C$. Based on the problem, we have: (1) $2T + 3C = 540$ and (2) $2T + 1C = 470$.

$2T + 3C = 540$

Solve for the cost of one chair

Subtract equation (2) from equation (1): $(2T + 3C) - (2T + 1C) = 540 - 470$. This simplifies to $2C = 70$.

$C = \frac{70}{2} = 35$

Calculate the total cost of 35 chairs

Now multiply the cost of one chair by 35: $35 \times 35 = 1225$.

$35 \times 35 = 1225$