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If 'A' stands for '├╖', 'B' stands for '├Ч', 'C' stands for '+', and 'D' stands for '-', then the resultant of which of the following would be 99?
28 C 39 B 3 D 12 A 7
28 B 39 C 3 A 12 D 7
28 A 39 D 3 B 12 C 7
28 D 39 A 3 C 12 B 7
28 D 39 A 3 C 12 B 7
Focus on the division symbol (A). The result must be a whole number, so test the option where the division allows perfect divisibility first.
Focus on the division symbol (A). The result must be a whole number, so test the option where the division allows perfect divisibility first.
Mapping the Operators
Given: A = /, B = *, C = +, D = -. Substituting these into the expressions: A = /, B = *, C = +, D = -.
Evaluate Option D
Expression D is 28 D 39 A 3 C 12 B 7. Replacing signs: 28 - 39 / 3 + 12 * 7. Apply BODMAS: 1) Division: 39 / 3 = 13. 2) Multiplication: 12 * 7 = 84. 3) Substitution: 28 - 13 + 84. 4) Addition/Subtraction: 15 + 84 = 99. Matches the target.
A: 28+393-12/7 is not an integer. B: 2839+3/12-7 results in 1092.25. C: 28/39-3*12+7 is not an integer.
D is correct because replacing the symbols in 28 D 39 A 3 C 12 B 7 with 28 - 39 / 3 + 12 * 7 follows BODMAS rules to result in exactly 99.
In arithmetic expression questions, always perform the division operation first, as it often eliminates invalid options that result in fractions.