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B is thrice as good a workman as A and therefore is able to finish a job in 60 days less than A. Working together, they can do it in:
2221тАЛ days
30 days
25 days
20 days
2221тАЛ days
Use the efficiency ratio 3:1. The time ratio is 1:3. The difference of 2 units equals 60 days, so 1 unit = 30 days (A takes 90, B takes 30). Combined time = (90 * 30) / (90 + 30) = 2700 / 120 = 22.5 days.
B is three times as efficient as A, and the time taken by B to finish a job is 60 days less than A.
TimeтИЭEfficiency1тАЛ, TimeABтАЛ=A+BA├ЧBтАЛ
Use the efficiency ratio 3:1. The time ratio is 1:3. The difference of 2 units equals 60 days, so 1 unit = 30 days (A takes 90, B takes 30). Combined time = (90 * 30) / (90 + 30) = 2700 / 120 = 22.5 days.
Confusing the ratio of efficiency with the ratio of time; remember that time taken is inversely proportional to efficiency.
Establish efficiency and time ratios
Since B is thrice as efficient as A, the ratio of efficiency is EBтАЛ:EAтАЛ=3:1. Consequently, the ratio of time taken is TAтАЛ:TBтАЛ=1:3.
TAтАЛ:TBтАЛ=1:3
Calculate individual time
Let TAтАЛ=3x and TBтАЛ=x. Given TAтАЛтИТTBтАЛ=60, we have 3xтИТx=60, which gives x=30. Thus, A takes 90 days and B takes 30 days.
TAтАЛ=90,TBтАЛ=30
Calculate combined time
The time taken by both working together is calculated using the formula TtotalтАЛ=TAтАЛ+TBтАЛTAтАЛ├ЧTBтАЛтАЛ.
TtotalтАЛ=90+3090├Ч30тАЛ=1202700тАЛ=22.5
A is correct because the combined time for A and B to finish the job is 22.5 days, which is 2221тАЛ days.
This inverse relationship between speed and time is the fundamental principle used in Pipe and Cistern problems and Speed-Distance-Time problems.