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Find the value of (10001+12)(10001тИТ12).
1000019857
10019857
1000190857
100019857
100019857
Use the algebraic identity (a+b)(aтИТb)=a2тИТb2 where a=10001 and b=12. Calculate 100012=100020001 and 122=144, then subtract.
The expression to evaluate is (10001 + 12)(10001 - 12).
(a+b)(aтИТb)=a2тИТb2
Use the algebraic identity (a+b)(aтИТb)=a2тИТb2 where a=10001 and b=12. Calculate 100012=100020001 and 122=144, then subtract.
Students often try to expand it by full multiplication instead of recognizing the difference of squares identity, leading to calculation errors.
Identify the pattern
The given expression (10001+12)(10001тИТ12) matches the algebraic identity (a+b)(aтИТb)=a2тИТb2.
(a+b)(aтИТb)=a2тИТb2
Substitute values
Substitute a=10001 and b=12 into the formula.
(10001+12)(10001тИТ12)=100012тИТ122
Perform the calculation
Calculate 100012=(10000+1)2=100000000+20000+1=100020001. Then subtract 122=144.
100020001тИТ144=100019857
D is correct because the result of the calculation (100012тИТ122) is 100019857.
This identity is frequently used in mental math and simplification problems in RRB and SSC exams to quickly evaluate large numbers by shifting them close to powers of 10.