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With an initial velocity of 10┬аm/s, an object is thrown vertically upwards. The maximum height attained by the object is ________. (Assume g=10┬аm/s2)
5 m
100 m
1 m
20 m
5 m
To calculate the maximum height attained by an object thrown vertically upwards, we use the kinematic equation v2=u2+2as. At the maximum height, the final velocity v becomes 0, the initial velocity u=10m/s, and the acceleration due to gravity a=тИТg=тИТ10m/s2.
To calculate the maximum height attained by an object thrown vertically upwards, we use the kinematic equation v2=u2+2as. At the maximum height, the final velocity v becomes 0, the initial velocity u=10m/s, and the acceleration due to gravity a=тИТg=тИТ10m/s2.
Think of throwing a ball up; it gradually slows down as Earth's gravity pulls it back, eventually coming to a momentary halt at the peak before it starts falling down.
v2=u2+2as тАФ Kinematic equation of motion
h=2gu2тАЛ тАФ Formula for maximum height attained
The object moves against the acceleration due to gravity. The kinetic energy possessed at the start is converted into potential energy until the velocity reaches zero at the peak, defined by the conservation of energy principle or kinematic equations.
At maximum height, the final velocity v is 0m/s.
Acceleration due to gravity acts in the opposite direction to the initial velocity, hence a=тИТ10m/s2.
The calculation is h=2├Ч10102тАЛ=20100тАЛ=5meters.
Ballistic trajectory calculations
Safety clearance estimations
Standard value of g is approximately 9.81m/s2, but 10m/s2 is used here as instructed.
Option B (100 m) is the result of incorrect squaring or formula usage.
Option D (20 m) is a common distraction resulting from ignoring the factor of 2 in the denominator.
A is correct тАФ The maximum height attained is calculated as h=2gu2тАЛ=20100тАЛ=5m.
Always verify units before plugging values into equations; here, velocity is m/s and acceleration is m/s┬▓, ensuring the result is in meters.
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