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The area (in cm2) of an equilateral triangle whose altitude from vertex is 9 cm, is:
493
233
123
273
273
For an equilateral triangle with altitude h, the area is given by the formula 3h2. Since h=9, h2=81, and 81/3=273.
Altitude (h) of an equilateral triangle = 9 cm
Area=3h2
For an equilateral triangle with altitude h, the area is given by the formula 3h2. Since h=9, h2=81, and 81/3=273.
Students often use the area formula 43a2 where 'a' is the side length, but calculate 'a' using h=23a first. Failing to simplify 381 into 273 leads to errors.
Identify the relationship between altitude and side
In an equilateral triangle with side length 'a', the altitude 'h' is related to 'a' by the formula h=23a. Thus, a=32h.
a=32×9=318
Calculate the area using the standard formula
The area of an equilateral triangle is 43a2. Substituting a=318 gives: Area=43×(318)2.
Area=43×3324=43×108=273
Final Verification
The calculated area is 273cm2, which matches option D.
Area=273
D is correct because the area calculated using the formula Area=3h2 with h=9 is 273cm2.
This formula Area=3h2 is extremely useful in time-pressured exams like RRB to save the step of finding the side length first.