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1+cosθ−sin2θsinθ(1+cosθ),0°<θ<90°,is equal to:
tanθ
cotθ
secθ
cscθ
secθ
Substitute a standard angle value such as θ = 60° into the expression to quickly evaluate it: sin 60° = √3/2, cos 60° = 1/2. The expression yields tan 60° = √3.
An algebraic trigonometric expression: (sin θ(1 + cos θ)) / (1 + cos θ - sin² θ) where 0° < θ < 90°.
sin2θ+cos2θ=1
Substitute a standard angle value such as θ = 60° into the expression to quickly evaluate it: sin 60° = √3/2, cos 60° = 1/2. The expression yields tan 60° = √3.
Students often struggle to simplify the denominator (1 + cos θ - sin² θ) by forgetting the fundamental identity sin² θ = 1 - cos² θ.
Simplify the denominator
Use the identity sin2θ=1−cos2θ to rewrite the denominator 1+cosθ−sin2θ.
1+cosθ−(1−cos2θ)=cosθ+cos2θ=cosθ(1+cosθ)
Substitute back into the expression
Replace the original denominator with the simplified form to cancel common terms.
cosθ(1+cosθ)sinθ(1+cosθ)
Final simplification
Cancel the common term (1+cosθ) from the numerator and denominator.
cosθsinθ=tanθ
C is correct because the trigonometric expression simplifies directly to tanθ using the identity sin2θ=1−cos2θ.
This type of simplification frequently appears in problems involving identity verification and calculus limits involving trigonometric functions.