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Refer to the given series and answer the question that follows (all numbers are single-digit numbers only, and all counting is to be done from left to right).
How many such odd digits are there, each of which is immediately preceded by an even digit and also immediately followed by an odd digit?
6
5
4
3
4
Scan for sequences of (Even, Odd, Odd) digits by identifying every odd digit and checking its neighbors.
Scan for sequences of (Even, Odd, Odd) digits by identifying every odd digit and checking its neighbors.
Analyze the series
The given series is: 4, 0, 8, 3, 5, 6, 2, 1, 6, 4, 1, 4, 3, 8, 7, 9, 0, 6, 9, 3, 4, 1, 3, 0, 2, 7, 1, 8, 8, 9. We need to identify odd digits (1, 3, 5, 7, 9) that are preceded by an even digit (0, 2, 4, 6, 8) and followed by an odd digit.
Identify sequences (Even, Odd, Odd)
Scanning the series for triplets (Even, Odd, Odd): 1) (8, 3, 5) - Yes (8=E, 3=O, 5=O); 2) (6, 1, 6) - No; 3) (4, 1, 4) - No; 4) (8, 7, 9) - Yes (8=E, 7=O, 9=O); 5) (6, 9, 3) - Yes (6=E, 9=O, 3=O); 6) (4, 1, 3) - Yes (4=E, 1=O, 3=O); 7) (0, 2, 7) - No; 8) (2, 7, 1) - Yes (2=E, 7=O, 1=O).
Count the valid instances
The valid triplets found are: (8,3,5), (8,7,9), (6,9,3), (4,1,3), and (2,7,1). Total count is 5.
A: Represents the number 4 which is incorrect, C: Represents the number 6 which is incorrect, D: Represents the number 3 which is incorrect.
B is correct because there are exactly 5 occurrences of an odd digit preceded by an even digit and followed by an odd digit in the provided sequence.
When counting specific patterns in long sequences, group them into triplets to avoid missing overlaps or counting out of sequence.