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Based on the English alphabetical order, three of the following four letter-group pairs are alike in a certain way and thus form a group. Which pair does not belong to that group? (Note: The selection of the odd one is not based on the number of consonants/vowels or their positions in the letter groups.)
OJ-MP
SN-QU
QL-OR
UP-SV
QL-OR
Calculate the numerical difference between the letters in each pair. If the difference in pair X-Y is different from the majority, that is your odd one out.
Calculate the numerical difference between the letters in each pair. If the difference in pair X-Y is different from the majority, that is your odd one out.
Analyze Letter Differences
Map each letter to its alphabetical position (A=1, B=2, ..., Z=26) and calculate the difference (2nd letter - 1st letter) for the first letter of each cluster and the second letter of each cluster.
Evaluate Each Pair
OJ-MP: O(15) to J(10) is -5. M(13) to P(16) is +3. SN-QU: S(19) to N(14) is -5. Q(17) to U(21) is +4. QL-OR: Q(17) to L(12) is -5. O(15) to R(18) is +3. UP-SV: U(21) to P(16) is -5. S(19) to V(22) is +3.
Identify the Outlier
Pairs OJ, QL, and UP all follow a pattern where the first letter of the first cluster and the first letter of the second cluster have a difference of -5, and the second letters have a difference of +3. SN-QU is the only one where the second letters have a difference of +4.
A, C, and D are incorrect because they all follow the consistent pattern of -5 jump for the first letter and +3 jump for the second letter; B is the only one that deviates.
B is correct because the pair SN-QU follows a +4 difference in the second half of the cluster, whereas all other options maintain a +3 difference.
When faced with letter-cluster analogies, always check the difference between corresponding positions first before assuming complex shifting rules.
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