Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
Select the set in which the numbers are related in the same way as are the numbers of the following sets. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 тАУ Operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) (25, 5, 20) (40, 8, 32)
(100, 16, 64)
(80, 16, 60)
(80, 16, 64)
(80, 14, 64)
(80, 16, 64)
The pattern is (First Number - Third Number) = Second Number, or more simply, First Number = Second Number + Third Number.
The pattern is (First Number - Third Number) = Second Number, or more simply, First Number = Second Number + Third Number.
Analyze the given sets
Set 1: (25, 5, 20). Here, 25 - 20 = 5. Set 2: (40, 8, 32). Here, 40 - 32 = 8. In both cases, the relationship is (First Number) = (Second Number) + (Third Number).
Evaluate the options
We need to find a set (A, B, C) where A = B + C. Option A: (100, 16, 64) тЖТ 16 + 64 = 80 (Not100). Option B: (80, 16, 60) тЖТ 16 + 60 = 76 (Not80). Option C: (80, 16, 64) тЖТ 16 + 64 = 80. This matches the rule. Option D: (80, 14, 64) тЖТ 14 + 64 = 78 (Not80).
A is incorrect because 16 + 64 = 80, not 100. B is incorrect because 16 + 60 = 76, not 80. D is incorrect because 14 + 64 = 78, not 80.
C is correct because the logic follows the pattern where the first number is the sum of the second and third numbers (16 + 64 = 80).
In number set problems, always check simple addition or subtraction relations between the three numbers first, as they cover the vast majority of these questions in competitive exams.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants