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Lavanya got married 10 years ago. Now her age is 151тАЛ times her age at the time of marriage. Her son's present age is one-tenth of her present age. Find her son's present age.
6 years
5 years
20 years
12 years
6 years
Since the age is 6/5 times, the difference (1 unit) corresponds to the 10 years passed. Therefore, 1 unit = 10 years, making her present age (6 units) = 60 years.
Lavanya's marriage was 10 years ago. Present age is 6/5 times her age at marriage. Son's age is 1/10 of her present age.
x=56тАЛ(xтИТ10)
Since the age is 6/5 times, the difference (1 unit) corresponds to the 10 years passed. Therefore, 1 unit = 10 years, making her present age (6 units) = 60 years.
Confusing the age at marriage (xтИТ10) with the age 10 years ago (xтИТ10) and setting up the ratio incorrectly.
Define variables
Let Lavanya's present age be x years. The age at the time of her marriage 10 years ago was (xтИТ10) years.
AgemarriageтАЛ=xтИТ10
Set up the equation
According to the problem, her present age is 151тАЛ (which is 56тАЛ) times her age at the time of marriage.
x=56тАЛ(xтИТ10)
Solve for x
Multiply both sides by 5: 5x=6(xтИТ10)тЯ╣5x=6xтИТ60тЯ╣x=60. So, Lavanya's present age is 60 years.
x=60
Find the son's age
The son's present age is one-tenth of her present age.
AgesonтАЛ=101тАЛ├Ч60=6
A is correct because the calculation yields a present age of 60 for the mother, making the son's age 6 years.
Age problems often reduce to simple linear equations; identifying the time gap as the 'difference' in ratio units is the fastest way to solve them.