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C2тАЛH2тАЛ, C2тАЛH4тАЛ, and C2тАЛH6тАЛ belong to which group of hydrocarbons?
Alkane, alkyne, and alkene hydrocarbons, respectively
Alkane, alkene, and alkyne hydrocarbons, respectively
Alkene, alkyne, and alkane hydrocarbons, respectively
Alkyne, alkene, and alkane hydrocarbons, respectively
Alkyne, alkene, and alkane hydrocarbons, respectively
Hydrocarbons are classified by the number of bonds between carbon atoms. C2тАЛH2тАЛ (ethyne) is an alkyne, C2тАЛH4тАЛ (ethene) is an alkene, and C2тАЛH6тАЛ (ethane) is an alkane.
Hydrocarbons are classified by the number of bonds between carbon atoms. C2тАЛH2тАЛ (ethyne) is an alkyne, C2тАЛH4тАЛ (ethene) is an alkene, and C2тАЛH6тАЛ (ethane) is an alkane.
Think of it like a chain: Alkanes are a 'saturated' heavy chain with all links single, while Alkenes and Alkynes are 'unsaturated' chains with tightened double or triple-strength links holding the carbons together.
Remember 'ANE-ENE-YNE' corresponds to Single-Double-Triple bonds (alphabetical order of suffixes E, N, Y).
CnтАЛH2n+2тАЛ тАФ General formula for Alkanes
CnтАЛH2nтАЛ тАФ General formula for Alkenes
CnтАЛH2nтИТ2тАЛ тАФ General formula for Alkynes
The general formulas for these homologous series are: Alkanes have CnтАЛH2n+2тАЛ, Alkenes have CnтАЛH2nтАЛ, and Alkynes have CnтАЛH2nтИТ2тАЛ. For n=2, these formulas yield C2тАЛH6тАЛ, C2тАЛH4тАЛ, and C2тАЛH2тАЛ respectively, which dictates their chemical bonding: single, double, and triple bonds between carbon atoms.
Alkanes are saturated hydrocarbons containing only carbon-carbon single bonds.
Alkenes and Alkynes are unsaturated hydrocarbons containing at least one carbon-carbon double or triple bond respectively.
The suffix tells you the bond type: -ane (single), -ene (double), -yne (triple).
Ethane is used as a fuel and chemical feedstock.
Ethene is a precursor for polyethylene plastic production.
Ethyne is used in oxy-acetylene welding.
For n=2, the molecules are Ethane (C2тАЛH6тАЛ), Ethene (C2тАЛH4тАЛ), and Ethyne (C2тАЛH2тАЛ).
Option D is the correct sequence as it matches the order given in the question: C2тАЛH2тАЛ (Alkyne), C2тАЛH4тАЛ (Alkene), and C2тАЛH6тАЛ (Alkane).
D is correct тАФ The sequence correctly identifies C2тАЛH2тАЛ as an alkyne, C2тАЛH4тАЛ as an alkene, and C2тАЛH6тАЛ as an alkane.
Always verify the 'n' value in the general formula CnтАЛHxтАЛ when given hydrocarbon chemical formulas to quickly identify the homologous series.
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