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What is the initial speed of any object if it is dropped from a height of 50┬аm?
20 m/s
0
25 m/s
50 m/s
0
When an object is 'dropped', it means it is released from rest without any initial external force applied to accelerate it. Therefore, at the exact moment of release (initial position), its velocity is zero.
When an object is 'dropped', it means it is released from rest without any initial external force applied to accelerate it. Therefore, at the exact moment of release (initial position), its velocity is zero.
Think of holding a ball in your hand; before you let go, it is motionless. The moment you open your fingers to 'drop' it, it starts from a standstill, meaning its speed at that instant is 0.
u=0┬аm/s тАФ Initial velocity for a dropped object
v2=u2+2gh тАФ Final velocity after falling height h
According to the principles of kinematics in a gravitational field, the motion of a freely falling body is described by the equation of motion v=u+at. Since the object is dropped, the initial velocity u is 0┬аm/s. The only acceleration acting on the body is the acceleration due to gravity (gтЙИ9.8┬аm/s2).
The word 'dropped' implies initial velocity u=0.
The height of 50 m is relevant for calculating final impact velocity or time of fall, but does not affect the initial state.
Acceleration due to gravity g acts downwards during the fall.
Calculating time of flight for falling objects.
Determining impact velocity using kinematics equations.
Height h=50┬аm is extraneous information for this specific question.
If an object were 'thrown' downwards, the initial velocity would be greater than zero.
B is correct тАФ By definition, an object that is dropped starts from a state of rest, meaning its initial speed is 0┬аm/s.
Always distinguish between 'dropped' (u=0) and 'thrown' (u>0) in physics problems to avoid errors in applying equations of motion.
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