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If glucose:: six-carbon molecule, then pyruvate:: _________.
four-carbon molecule
five-carbon molecule
two-carbon molecule
three-carbon molecule
three-carbon molecule
Glucose (C6H12O6) is a six-carbon molecule that undergoes glycolysis in the cytoplasm of cells to be broken down into two molecules of pyruvate, which are each three-carbon molecules (CH3COCOO−). This is the initial stage of cellular respiration, common to both aerobic and anaerobic pathways.
Glucose (C6H12O6) is a six-carbon molecule that undergoes glycolysis in the cytoplasm of cells to be broken down into two molecules of pyruvate, which are each three-carbon molecules (CH3COCOO−). This is the initial stage of cellular respiration, common to both aerobic and anaerobic pathways.
Think of glucose as a large six-piece candy bar that needs to be split into two smaller, three-piece packs before it can be processed further for energy inside the cellular 'factory' (mitochondria).
C6H12O6→2C3H4O3+2ATP+2NADH
In the process of glycolysis, one molecule of glucose (6 carbons) is oxidized through a series of enzyme-catalyzed reactions into two molecules of pyruvate (3 carbons each). This occurs in the cytosol and yields a net gain of 2 ATP and 2 NADH molecules per glucose molecule, regardless of whether oxygen is present.
Glycolysis takes place in the cytoplasm of the cell.
It is the first step of both aerobic respiration and fermentation.
One molecule of glucose (6 carbons) yields two molecules of pyruvate (3 carbons each).
Cellular respiration
Metabolic energy production
Glucose is a hexose sugar.
Pyruvate is the salt form of pyruvic acid.
Option C (two-carbon molecule) describes Acetyl-CoA, which is formed after pyruvate enters the mitochondria.
D is correct — Since glucose is a 6-carbon molecule, glycolysis splits it into two 3-carbon pyruvate molecules.
Remember that in aerobic respiration, pyruvate then undergoes oxidative decarboxylation to become a 2-carbon Acetyl-CoA, which enters the Krebs cycle.
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