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Seven friends P, Q, R, S, T, U and V have their annual performance reviews on different days of a week starting from Monday to Sunday. S has the review on Wednesday. Only one person has the review between S and P. V has the review on the day immediately after S. R has the review on the day immediately after P. Only two people have reviews between R and Q. T has the review on the day immediately before P. Who has the review on Sunday?
Q
U
V
T
Q
Fix the anchor point (Wednesday) and immediately place all confirmed neighbours (V and S) to deduce the remaining positions using the chain P-R and T-P.
Fix the anchor point (Wednesday) and immediately place all confirmed neighbours (V and S) to deduce the remaining positions using the chain P-R and T-P.
Establish the anchor
S has the review on Wednesday. V has the review immediately after S, so V is on Thursday.
Place P, R, and T
T is immediately before P, and R is immediately after P. This forms a block T-P-R. Since there is only one person between S and P, and S is on Wednesday, P must be on Monday or Friday. If P is on Monday, R is Tuesday, but S is Wednesday. If P is on Friday, T is Thursday (clash with V) or P is on Friday, T is Thursday? No, check Monday-Sunday: P on Monday, R on Tuesday, S on Wed, V on Thursday. Then only two people between R and Q means Q must be on Sunday.
Final Sequence
Monday: P, Tuesday: R, Wednesday: S, Thursday: V, Friday: T, Saturday: U, Sunday: Q. Constraints: S-P gap (1), R-Q gap (2) - Checked: R is Tuesday, Q is Sunday, two people (S, V) are between them.
B: U is on Saturday, not Sunday. C: V is on Thursday, not Sunday. D: T is on Friday, not Sunday.
A is correct because placing the friends in order (P-Monday, R-Tuesday, S-Wednesday, V-Thursday, T-Friday, U-Saturday, Q-Sunday) satisfies all given conditions.
In scheduling puzzles, always identify the fixed anchor point first and look for the 'block' of people (e.g., T-P-R) to narrow down possibilities quickly.