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Six babies Ria, Sia, Tia, Urja, Vani and Winnie are born one after the other but not necessarily in the same order. All of them were born in different cities. Only two babies were born before the one who was born in Raipur. Only one baby was born between Sia, who was born in Delhi and the baby born in Raipur. Tia was born before Urja and just after the baby born in Haridwar. Tia was not born in Raipur. Ria was born in Bhopal and just before Vani. Tia was born immediately before the baby born in Ballia. Winnie was not born in Pune. Where was Winnie born?
Ballia
Haridwar
Delhi
Pune
Haridwar
Map fixed positions first (e.g., Raipur at 3rd) then link blocks (Haridwar-Tia-Ballia) to fill remaining slots.
Map fixed positions first (e.g., Raipur at 3rd) then link blocks (Haridwar-Tia-Ballia) to fill remaining slots.
Establish fixed positions
There are 6 babies. 'Only two babies were born before Raipur' means Raipur is in position 3. 'Only one baby between Sia (Delhi) and Raipur' implies Sia is at position 1 or 5. Since Tia is after Haridwar, Sia must be at 1.
Placement of blocks
The sequence is Haridwar тЖТ Tia тЖТ Ballia. This block of three must fit in positions 4, 5, 6 because position 3 is Raipur. Thus, Haridwar = 4, Tia = 5, Ballia = 6.
Assign remaining names and cities
Ria (Bhopal) and Vani are consecutive. They must occupy positions 2 and 3. Ria is at 2, Vani is at 3 (Raipur). This leaves Winnie at position 4 (Haridwar) and Urja at position 1 (Delhi).
A: Ballia is the city of the 6th baby, C: Delhi is the city of the 1st baby (Urja), D: Pune is where the 2nd baby (Ria) was not born as per the constraint mapping, and Winnie is verified to be in Haridwar.
B is correct because the sequence is 1:Urja(Delhi), 2:Ria(Bhopal), 3:Vani(Raipur), 4:Winnie(Haridwar), 5:Tia(Pune), 6:Unnamed(Ballia).
In scheduling puzzles, always look for the longest contiguous block of variables to restrict the search space quickly.
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