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Solve: (a + b + c)(a┬▓ + b┬▓ + c┬▓ - ab - bc - ca) =?
a3+b3+c3тИТ3abc
a3+b3+c3+3abc
(a+b+c)3
a2+b2+c2
a3+b3+c3тИТ3abc
Substitute small integer values like a=1,b=1,c=1 into the expression to quickly evaluate and match with the options.
An algebraic product of a trinomial and a quadratic expression involving variables a, b, and c.
(a+b+c)(a2+b2+c2тИТabтИТbcтИТca)=a3+b3+c3тИТ3abc
Substitute small integer values like a=1,b=1,c=1 into the expression to quickly evaluate and match with the options.
Confusing the sign of the 3abc term or misidentifying it with the expansion of (a+b+c)3.
Identify the Algebraic Identity
Recognize that the given expression is a standard algebraic identity for the product of a trinomial and a second-degree polynomial.
(a+b+c)(a2+b2+c2тИТabтИТbcтИТca)
Apply Expansion Formula
Multiplying each term yields the well-known expansion formula where all cross terms cancel out, leaving the sum of cubes minus 3abc.
a3+b3+c3тИТ3abc
Verification via Substitution
Let a=1,b=1,c=1. The given expression evaluates to (3)(1+1+1тИТ1тИТ1тИТ1)=3(0)=0. Option A evaluates to 13+13+13тИТ3(1)(1)(1)=3тИТ3=0.
13+13+13тИТ3(1)(1)(1)=0
A is correct because the product expands directly to the standard algebraic identity a3+b3+c3тИТ3abc.
In competitive exams, variations of this identity often test the condition where a+b+c=0, which directly simplifies the equation to a3+b3+c3=3abc.