Join 60,000+ competitive exam aspirants
or with email
Your Cart
Subtotal₹0
Total₹0
Examoogle • User • info@examoogle.com • EE-2024-8821
Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
Join 60,000+ competitive exam aspirants
The average score of a cricketer in 20 matches is 40 runs. If his highest score in a match was 78 runs, what is the average of his scores in the remaining 19 matches?
34
36
40
38
38
Calculate the total runs for 20 matches (20 × 40 = 800), subtract the highest score (800 - 78 = 722), and divide by the remaining matches (722 / 19). For quick division: 19 × 30 = 570, remaining 152; 19 × 8 = 152. Thus, 30 + 8 = 38.
Number of matches = 20, Average score of 20 matches = 40 runs, Highest score in a single match = 78 runs.
Average=NumberofUnitsTotalSum
Calculate the total runs for 20 matches (20 × 40 = 800), subtract the highest score (800 - 78 = 722), and divide by the remaining matches (722 / 19). For quick division: 19 × 30 = 570, remaining 152; 19 × 8 = 152. Thus, 30 + 8 = 38.
Many students subtract 1 from the average (40 - 1 = 39) or fail to realize the count of matches reduces to 19, leading to an incorrect divisor.
Calculate Total Runs
To find the total runs in 20 matches, multiply the number of matches by the average score.
Total20=20×40=800
Exclude the Highest Score
Subtract the highest score from the total runs to get the sum of the remaining 19 matches.
Sum19=800−78=722
Calculate New Average
Divide the sum of the remaining 19 matches by 19 to find the new average.
Average19=19722=38
D is correct because the sum of 19 matches is 722, and 722 divided by 19 equals 38.
This concept of 'change in average upon exclusion' is identical to weight change problems in mixtures and alligation or personnel turnover statistics.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download • 100K+ Aspirants