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ElectricalPower System
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The corona loss on a particular system at 50Hz is 1 kWтИХ phase тИХ km. The corona loss on the same system with supply frequency 25 Hz will be

A

1 kW/phase/km

B

0.5 kW/phase/km

C

0.667 kW/phase/km

D

None of the above

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalPower System
Option C

0.667 kW/phase/km

Quick Summary:

Corona loss in a transmission line is calculated using Peek's formula, where loss is directly proportional to (f+25)(f + 25)(f+25), where fff is the supply frequency. By calculating the ratio of losses at 50 Hz and 25 Hz, the new loss is found to be 0.667 kW/phase/km.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

Corona loss in a transmission line is calculated using Peek's formula, where loss is directly proportional to (f+25)(f + 25)(f+25), where fff is the supply frequency. By calculating the ratio of losses at 50 Hz and 25 Hz, the new loss is found to be 0.667 kW/phase/km.

ЁЯФв Key Formulas

PтИЭ(f+25)P \propto (f + 25)PтИЭ(f+25) тАФ Relationship between corona loss and frequency

P1P2=f1+25f2+25\frac{P_1}{P_2} = \frac{f_1 + 25}{f_2 + 25}P2тАЛP1тАЛтАЛ=f2тАЛ+25f1тАЛ+25тАЛ тАФ Ratio calculation formula

тЪЩя╕П Working Principle

Corona occurs when the electric field intensity at the conductor surface exceeds the dielectric strength of air. Peek's empirical formula for corona power loss is P=244тЛЕf+25╬┤rD(VтИТVc)2├Ч10┬░тИТ5P = 244 \cdot \frac{f+25}{\delta} \sqrt{\frac{r}{D}} (V-V_c)^2 \times 10┬░{-5}P=244тЛЕ╬┤f+25тАЛDrтАЛтАЛ(VтИТVcтАЛ)2├Ч10┬░тИТ5 kW/phase/km. Since all parameters except frequency (fff) remain constant, the power loss PPP is proportional to (f+25)(f + 25)(f+25).

ЁЯУМ Key Points
  • тЦ╕

    Corona loss is dependent on the frequency of the supply voltage.

  • тЦ╕

    The factor (f + 25) is derived from Peek's formula.

  • тЦ╕

    Lower frequency leads to lower corona loss for the same voltage levels.

тЬЕ Advantages
  • тЦ╕

    Reduces power dissipation in long-distance lines.

  • тЦ╕

    Minimizes interference with communication lines.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Occurs primarily at high voltages (Extra High Voltage lines).

  • тЦ╕

    Causes ozone formation and chemical corrosion.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    High Voltage Transmission (EHV/UHV).

  • тЦ╕

    Design of bundled conductors.

ЁЯУД Additional Information
  • тЦ╕

    Peek's formula is valid for fair weather conditions.

  • тЦ╕

    Option B (0.5 kW) is incorrect because the loss is not directly proportional to frequency alone, but to the term (f+25)(f+25)(f+25).

ЁЯУК Diagram / Illustration
Corona Loss Ratio FormulaPтВБ / PтВВ = (fтВБ + 25) / (fтВВ + 25)PтВБ = 1 kW, fтВБ = 50 Hz, fтВВ = 25 HzPтВВ = 1 ├Ч (50/75) = 0.667 kW
тЬЕ

C is correct тАФ Applying the ratio P1P2=f1+25f2+25\frac{P_1}{P_2} = \frac{f_1 + 25}{f_2 + 25}P2тАЛP1тАЛтАЛ=f2тАЛ+25f1тАЛ+25тАЛ with f1=50f_1 = 50f1тАЛ=50 Hz and f2=25f_2 = 25f2тАЛ=25 Hz yields P2=1├Ч5075=0.667P_2 = 1 \times \frac{50}{75} = 0.667P2тАЛ=1├Ч7550тАЛ=0.667 kW/phase/km.

Core Concepts Used
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Corona Loss Peek's Formula Frequency Dependence
ЁЯТб EXAM TIP

Always verify if a parameter (like frequency) is in the numerator or part of a binomial expression in transmission formulas before assuming direct proportionality.

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